Please See Attachment

Please see attachment

 

Answer:

Coordinate 6 is -(m) or -m  and  coordinate 3 is (-n) or -n.

Step-by-step explanation:

Point A (m, n) is on Quadrant III where x and y coordinates are negative.

Then coordinate 6 is -(m) or -m  and  coordinate 3 is (-n) or -n.


Comments

Post a Comment

Popular posts from this blog

Ur Opinion For The Last Time

Image
Ur opinion for the last time   If I were to die today, I would make the most of it. I will do what I have always longed to do along with my family. I would create a legacy of my own, one which people will remember me by. I will go to those who are important to me and let them know how big the parts they play in my life. Most importantly and last but not the least, I will repent my sins, go to church and thank God for the life he had made me experience.
Read more

How To Have A Good Human Relationships

How to have a good human relationships   1.Treat others with kindness and respect 2. Observe empathy and understand theor feelings. 3. Help people in need without asking anything in return 4. Participate in societal activities or issues. 5. Connect and bond with other people by means of recreational activities.
Read more

Margie Has Grades 86 68 And 79 In Her First Three Tests In Algebra What Grade Must She Obtain In The Fourth Test To Get An Average Of 78

Image
Margie has grades 86 68 and 79 in her first three tests in algebra what grade must she obtain in the fourth test to get an average of 78   Answer: The grade that she needs to get for the fourth test is 79. Further Explanation The process of solving this problem is quite easy. We can apply the concept in Statistics in this matter. In Statistics, statistician needs to consider the middle value or the measures of central tendency of the given data. Measures of Central Tendency 1. The mean or average 2. The median 3. The mode In this problem, we are going to use the mean since the problem is talking about average. The formula for the mean is   . Steps in Solving the Needed Grade 1. Assume a variable for the unknown grade. 2. Substitute the value of into the formula. 3. Do cross multiplication. 4. Apply the inverse operation to solve for the unknown variable. Solution: Let be the needed grade.                                       Base on the solution process above, it clearly says...
Read more